Exercises

Exercises#

The following problems will be useful practice for the graphing method of solution.

## Do not change this cell, only execute it. 
## This cell initializes Python so that pandas, numpy and scipy packages are ready to use.

import datascience
%matplotlib inline
import matplotlib.pyplot as plots
plots.style.use('fivethirtyeight')
import numpy as np
import scipy as sp
import math
import scipy.stats as stats
from fractions import Fraction

C:\Users\robbs\anaconda3\envs\GameTheory\Lib\site-packages\datascience\maps.py:13: UserWarning: pkg_resources is deprecated as an API. See https://setuptools.pypa.io/en/latest/pkg_resources.html. The pkg_resources package is slated for removal as early as 2025-11-30. Refrain from using this package or pin to Setuptools<81.
  import pkg_resources

Exercise 1

Solve the game using the graphing method backstopped by oddments.

\[\begin{split}\begin{array}{cc}&\textbf{Rose}\\\textbf{Colin}& \begin{array}{r|cccc} & A & B & C & D \\ \hline A & 2 & 6 & 1 & 4 \\ B & 5 & 0 & 7 & 3\end{array} \end{array}\end{split}\]

Exercise 2

Solve the game using the graphing method backstopped by oddments.

\[\begin{split}\begin{array}{cc}&\textbf{Rose}\\\textbf{Colin}& \begin{array}{r|cc} & A & B\\ \hline A & 1 & 8 \\ B & 3 & 2 \\ C & 7 & 0 \\ D & 4 & 5 \end{array} \end{array}\end{split}\]

Exercise 3

Solve the game using the graphing method backstopped by oddments.

\[\begin{split}\begin{array}{cc}&\textbf{Rose}\\\textbf{Colin}& \begin{array}{r|ccccc} & A & B & C & D & E\\ \hline A & 10 & 2 & 5 & 8 & 3 \\ B & 1 & 9 & 6 & 2 & 7 \end{array} \end{array}\end{split}\]

Exercise 4

Solve the game using the graphing method backstopped by oddments.

\[\begin{split}\begin{array}{cc}&\textbf{Rose}\\\textbf{Colin}& \begin{array}{r|rr} & A & B\\ \hline A & -2 & 4 \\ B & 3 & -1 \\ C & 0 & 2 \end{array} \end{array}\end{split}\]

Exercise 5

Solve the game using the graphing method backstopped by oddments.

\[\begin{split}\begin{array}{cc}&\textbf{Rose}\\\textbf{Colin}& \begin{array}{r|cccc} & A & B & C\\ \hline A & 4 & 1 & 8 \\ B & 2 & 5 & 0\end{array} \end{array}\end{split}\]